Pls help me...Circles A and B have radii 5 and 7, respectively, and the distance between their centers A and B is 6. If the two circles intersect at points M and N, find the length of the common chord MN.
For ALL geometry questions you MUST make a drawing. Have you done that already?
|dw:1389617887045:dw|
Something like this, preferable on paper with a pencil
yup im done...
Hm wait a moment, I will make a drawing on paper, this doesnt help me so much
is x = 1?
i mean h =2 sqrt 6...
so MN = 4 sqrt 6?
I dont know yet. But I would prefer if you posted your way of solving it instead of just posting numbers
Yes answer is 4sqrt6
equate area of triangle 1/2*h*6=area by herons formula
ok thank you so much...i must only use the pythagorean theorem..right?
This is possible since common chord is always perpendicular to the line joining centres of a circle and is bisected by it.
yep...but at first it seems impossible since the distance of the 2 centers is 6 yet the radii are 5 and 7...
how to apply heron's formula here MayankD?
Yea the figure is somewhat like |dw:1389618707171:dw|
yep dts ryt..
Area of a triangle=sqrt(s*(s-a)*(s-b)*(s-c)) where s is semi perimeter of triangle and a b and c are the sides of the traingle
Yes I have \[4\sqrt{6}\] as well.
Please help me... Suppose f(t)=A*2^(0.02t) represents the bacteria in a culture t minutes from the start of an experiment. Give an expression for the number of minutes needed for the bacteria to double.HW BWT DS??
F(t)=A*2^(0.02(t+50))
d answer here is 50ln2 but i dont know the solution
What is the exact question?
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