Question

Write the equation of the line that passes through (–4, 3) and is perpendicular to the line y=7/5x -3/5?

A.
5x + 7y = 1
B.
7x + 5y = –13
C.
7x + 5y = –1
D.
3x + 5y = 7

Answer 1

@Euler271

Answer 2

the line is in the form y = mx + b, where m is the slope and b in the y-intercept.

the slope in this case is 7/5.

the slope of perpendicular lines are the NEGATIVE RECIPROCAL of eachother.

so the slope of the line perpendicular to the line of slope m is (-1/m).

so the slope of the line perpendicular to our line here is (-5/7).

the y-intercept of the original line will not be used since it is irrelevant information in our case.

to find the equation of the line given the slope and given a point (Xo, Yo), you take:

\[(y - y_0) = m(x - x_0)\]\[y - 3 = \left(- \frac{ 5 }{ 7 } \right)(x - (-4))\]\[y = 3 - \frac{ 5 }{ 7 }x -\frac{ 20 }{ 7 }\]\[y = - \frac{ 5 }{ 7 } + \frac{ 1 }{ 7 }\]

Answer 3

is it A.

Answer 4

I think that it's A am I right?

Answer 5

yes (my bad for delay lol)