The measures of the angles of a triangle are in the extended ratio 3:6:11. what is the measure of the largest angle?
??
The side that has length 11 is too long to work with sides of lengths 3 and 6 to be able to have a triangle.
Yes: in other words, if the sides of length 3 and 6 were to be lined up straight, their combined length would come to 9, whereas the length of the longest side would be 11. No soap.
well the question isnt wrong. idk=/ something like 20x +6x + 11x = 180 ??
Sorry. Ignore what I wrote above. I misread the question.
It's the angles that are in that ratio, not the sides. My mistake.
the answer is 99 .. i think. thats my guess.
Oh, shoot. RED face. We were talking about side lengths here; the problem deals with ANGLES, not side lengths. If x is a constant of proportionality, then 3x+6x+11x=180 degrees (because the interior angles of a triangle always sum up to 180 degrees).
Since the angles are in the 3:6:11 ratio, let's call the angles 3x : 6x : 11x That means 3x + 6x + 11x = 180
Now we solve for x: 3x + 6x + 11x = 180 20x = 180 x = 9
Your guess? Just add up 3x and 6x and 11x and set them equal to 180; result is 20x=180. x+??
9 isnt an option
so 20?
Since we know x = 9, and the angle is 11x, we replace the x with 9: 11x = 11*9 = 99
yay i was right :D thanks!
Right. 9 is nothing more than a constant multiplier. 9 is not a measure of one of the angles. Mathstudent has the right idea.
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