Question

to the nearest tenth what is the distance between (7, -1) and (1, 4)

Answer 1

Use the distance formula \[d=\sqrt{(x _{2}+x _{1})^{2}+(y _{2}+y _{1})^{2}}\]

Answer 2

I tried that but i dont know where i would go to the nearest tenth.

Answer 3

So you plugged in the x and y values? what did you get?

Answer 4

√89

Answer 5

btw thank you for helping me!!!

Answer 6

hmm that doesn't seem right..?
you did \[d=\sqrt{(7+1)^{2}+(-1+4)^{2}}\] right

Answer 7

I think you added the 1 and 4 together and forgot that the 1 was negative

Answer 8

im trying it again

Answer 9

√61 ?

Answer 10

my last equation would simplify to this. Can you do it from here?
\[d=\sqrt{(8^{2})+(3^{2})}\]

Answer 11

64+9=73

Answer 12

yes. So now square root that and what do you get

Answer 13

I do remember how to

Answer 14

8.5440

Answer 15

okay and the first decimal space in the tenths place so round to the first decimal place and you have your answer

Answer 16

\[d=\sqrt{\left( x2-x1 \right)^{2}+\left( y2-y1 \right)^{2}}\]

Answer 17

\[d=\sqrt{\left( 1-7 \right)^{2}+\left( 4+1 \right)^{2}}=\sqrt{36+25}=\sqrt{51}=7.14=7.1\]

Answer 18

correction
\[d=\sqrt{36+25}=\sqrt{61}=7.81=7.8\]