Question

What is the equation in point-slope form of the line passing through (4, 0) and (2, 6)?

y = 4x − 2

y = 2x − 4

y = −3(x − 4)

y = 3(x + 4)

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 4}}\quad ,&{\color{blue}{ 0}})\quad &({\color{red}{ 2}}\quad ,&{\color{blue}{ 6}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-y_1={\color{green} m}(x-x_1)\quad \textit{point-slope form, plug in your values}\)

Answer 2

@jdoe0001 So, y - 4 = 6/-2 (x - 4) ?

Answer 3

And then I would distribute right?

Answer 4

yes

Answer 5

Thank you!

Answer 6

hmmm notice your values though -> y - 4 = 6/-2 (x - 4)
^ ^
(4, 4) ?

Answer 7

you have (4,0) and (2,6) to use, you don't have a (4,4) point

Answer 8

so using say (4, 0) will be y - 0 = 6/-2 (x - 4)
^ ^

Answer 9

then distribute