Solve the following system equations. 3y=12 2x+y=-16 and some of my answers are (-4,-10) (-10,4) (4,10) (3,3)

Question

anonymous · Answer

$$3y=12$$$$y=12\div3$$ y=4

Then plug y into the other equation to find x

anonymous · Answer

That isn't helping

anonymous · Answer

okay well your first equation is 3y=12 correct?

anonymous · Answer

Its all together

anonymous · Answer

isnt it 3y=12 and the other is 2x+y=-16

anonymous · Answer

no the question reads solve the following system of equations/  3y=12 2x+y=-16  my answers include (-4,-10) (-10,4) (4, 10) (3,3)

anonymous · Answer

yes a system of equations is two equations. there is a space between the 12 and the 2x.

anonymous · Answer

can u help me solve this

anonymous · Answer

yes. they are asking to solve for x and y

anonymous · Answer

so start by solving for y
 3y=12
y=12÷3
 y=4

anonymous · Answer

now sub 4 in for y in the other equation to find x

anonymous · Answer

Would it be 4,10

anonymous · Answer

-10,4

anonymous · Answer

2x + y = -16
2x + 4 = -16
2x = -16 - 4
2x = -20
x = -20/2
x = -10

Its a - 10.