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Mathematics 19 Online
OpenStudy (anonymous):

How do I find the slope and y intercepts of an equation?

OpenStudy (anonymous):

So my book is asking me to solve each system by graphing then tell whether the system has one solution, infinitely many solutions, or no solution. Well first I have to find slope and y intercept of the equations... I need to first figure out how to find the slope and y intercepts of the equation...

OpenStudy (anonymous):

My equations: 3x + y = 2, 4y = 12 - 12x. I wanna say that the slope of the first equation is 3 and the y intercept if 2. And I wanna say for equation 2, the slope is 12 and the y intercept is 4??

OpenStudy (anonymous):

Plz help!! @tHe_FiZiCx99

OpenStudy (the_fizicx99):

Well not really, It seems they're asking you to use substitution, convert 4y = 12 - 12x. into y = mx + b 4y = 12 - 12x. /4 /4 /4 y = 3 - 3x 3 is the y intercept -3 is the slope

OpenStudy (the_fizicx99):

For the first equation, the slope is -3 and the y intercept is 2

OpenStudy (anonymous):

What about the second equation?? @tHe_FiZiCx99

OpenStudy (anonymous):

And after i find those, then how would I graph it?

OpenStudy (the_fizicx99):

4y = 12 - 12x -----> y = 3 - 3x The y intercept is 3 The M or slope is -3 3x + y = 2 -3x -3x y = -3x + 2 The slope is -3 The y intercept is 2

OpenStudy (anonymous):

Okay with those, how would I graph it??

OpenStudy (the_fizicx99):

._. 3x + y = 2 {First} 4y = 12 - 12x {Second}

OpenStudy (anonymous):

Yes, thank you. Sorry...

OpenStudy (anonymous):

Now I have to graph this... How would I do that?

OpenStudy (the_fizicx99):

So to graph this you plug in y = -3x + 3 into 3x + y = 2 When i tried to do this it gave me different values for some reason, but they are parallel though

OpenStudy (anonymous):

How many solutions would it have?

OpenStudy (the_fizicx99):

None since its parallel

OpenStudy (the_fizicx99):

They never intersect

OpenStudy (the_fizicx99):

Since it kept giving me different values, I converted both into y = mx + b and plot them, thats how I know they're parallel, y = 3 -3x and y = 2 -3x (Also notice their slopes are the same as well, so they're parallel) lol y = 3 -3x Plot it at (0,3) and do rise/run Down 3 right 1 y = 2 -3x Plot it at (0,2) Rise/run Down 3 right 1

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