How do I find the slope and y intercepts of an equation?
So my book is asking me to solve each system by graphing then tell whether the system has one solution, infinitely many solutions, or no solution. Well first I have to find slope and y intercept of the equations... I need to first figure out how to find the slope and y intercepts of the equation...
My equations: 3x + y = 2, 4y = 12 - 12x. I wanna say that the slope of the first equation is 3 and the y intercept if 2. And I wanna say for equation 2, the slope is 12 and the y intercept is 4??
Plz help!! @tHe_FiZiCx99
Well not really, It seems they're asking you to use substitution, convert 4y = 12 - 12x. into y = mx + b 4y = 12 - 12x. /4 /4 /4 y = 3 - 3x 3 is the y intercept -3 is the slope
For the first equation, the slope is -3 and the y intercept is 2
What about the second equation?? @tHe_FiZiCx99
And after i find those, then how would I graph it?
4y = 12 - 12x -----> y = 3 - 3x The y intercept is 3 The M or slope is -3 3x + y = 2 -3x -3x y = -3x + 2 The slope is -3 The y intercept is 2
Okay with those, how would I graph it??
._. 3x + y = 2 {First} 4y = 12 - 12x {Second}
Yes, thank you. Sorry...
Now I have to graph this... How would I do that?
So to graph this you plug in y = -3x + 3 into 3x + y = 2 When i tried to do this it gave me different values for some reason, but they are parallel though
How many solutions would it have?
None since its parallel
They never intersect
Since it kept giving me different values, I converted both into y = mx + b and plot them, thats how I know they're parallel, y = 3 -3x and y = 2 -3x (Also notice their slopes are the same as well, so they're parallel) lol y = 3 -3x Plot it at (0,3) and do rise/run Down 3 right 1 y = 2 -3x Plot it at (0,2) Rise/run Down 3 right 1
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