Question

verify that parallelogram ABCD with vertices A (-5 -1),B(-9,6),C(-1,5) and D(3,-2) is a rhombus by showing it is a parallelogram with perpendicular diagonals

Answer 1

Help please :)

Answer 2

@Mertsj

Answer 3

i think the vertices are wrong? that is not a rhombus

Answer 4

the product of the gradient of the diagonals must equal to -1 for them to be perpendicular

Answer 5

IDK, that's the question though

Answer 6

crazy huh?

Answer 7

questions wrong then. :/

Answer 8

I copied and pasted, don't know how to answer it, can you help at all?

Answer 9

Anyone??

Answer 10

Can someone else give it a try????

Answer 11

Please?????

Answer 12

A (-5 -1),B(-9,6),C(-1,5) and D(3,-2)
midpoint of AC is (-5-1)/2 ,(-1+5)/2 --> (-3,2)
midpoint of BD is (-9+3)/2,(6-2)/2 --> (-3,2)
thus the diagonals AC and BD bisect each other hence ABCD is a ||gm

Answer 13

now slope of AC is (5-(-1))/(-1-(-5)) =6/4=3/2
again slope of BD is (-2-6)/(3-(-9)) = -8/12 =-2/3
slope of AC * slope of BD =3/2 *-2/3 =-1
hence AC and BD are at right angles
bcoz ABCD is a ||gm and the diagonals bisect each other at right angles it is a rhombus