Question

lyhgfufltb

Answer 1

\[\Delta F/\Delta t\] i have to find this

Answer 2

@phi @campbell_st

Answer 3

The formula for average change of rate of y=f(x) over [n,m] is\[\frac{ f(m)-f(n) }{ m-n }=\frac{ f(n)-f(m) }{ n-m }\]

Answer 4

Here, f(t)=16t^2 - 1.6t + 35
n=a
m=5

Answer 5

yeah but what i dont get what to do is with the a and f(a). what am i supposed to do with those? also its .16t^2

Answer 6

Plug it in the formula to get...\[\frac{ f( 5)-f(a)}{ 5-a }=\frac{ (0.16(5)^2-1.6(5)+35)-(0.16a^2-1.6a+35) }{ 5-a }=\frac{ (4-8+35)-( -0.16a^2-1.6a+35)}{ 5-a }\]

Answer 7

i can't see after the = in your post

Answer 8

Do you know what to do from here on?

Answer 9

sorry i meant i cant see the right side of the = sign. and wouldn't it be 5-a instead of a-5? would i just simplify it?

Answer 10

I multiplied -1 to both numerator and denominator.

Answer 11

And yes, exactly. You factor the numerator and cancel out the a-5.

Answer 12

what is the right side? i see .16a(a^2-10a/a-5

Answer 13

It's \[\frac{ 0.16(a^2-10a+25 }{ a-5 }\]

Answer 14

Sorry. I made a mistake up there.

Answer 15

I'll repost it here.

Answer 16

\[\frac{ 4-8+35-(0.16a^2-1.6a+35) }{ 5-a }=\frac{ 0.16a^2-1.6a+4 }{ a-5 }\]=

Answer 17

\[\frac{ 0.16(a^2-10a+25) }{ a-5 }\]

Answer 18

Can you simplify that?

Answer 19

yeah i got .16a-.8 and thats the answer in the book. thanks so much

Answer 20

welcome :)