Question

lim as h approaches 0 2x^6+6x^3 over 4x^5+3x^3

Answer 1

\[\huge\color{blue}{ \lim_{h \rightarrow 0}~\frac{2x^6+6x^3 }{4x^5+3x^3} } \]

Answer 2

you meant x not h, right ?

Answer 3

yes sorry its X

Answer 4

try to factor top and bottom out of x^3, cancel x^3 on top and bottom, and then plug in 0 for x.

Answer 5

\[\huge\color{red}{ \lim_{x \rightarrow 0}~\frac{2x^6+6x^3}{4x^5+3x^3} } \]
\[\huge\color{red}{ \lim_{x \rightarrow 0}~\frac{x^3(2x^3+6)}{x^3(4x^2+3)} } \]
\[\huge\color{red}{ \lim_{x \rightarrow 0}~\frac{(2x^3+6)}{(4x^2+3)} } \]

now plug in zero for x.

Answer 6

What is the answer ?

Answer 7

2

Answer 8

Yup, that's right.

Answer 9

thank you so much

Answer 10

You welcome!