A line is perpendicular to another line if m2=[-1/m1], where m1 is the slope of the original line and m2 is the slope of the perpendicular line. Which of the following equations represents the line that passes through the point (1, –1) and is perpendicular to the line below? http://media.education2020.com/evresources/2003-10-02-00-00_files/i0230003.jpg
What is the slope of that given line?
-1 right?
no, that's incorrect unfortunately
Start at the point (0,2) How many units must you go down to get to the same horizontal level as (1,-1)?
-1/2
@jim_thompson5910
Start at the point (0,2) How many units must you go down to get to the same horizontal level as (1,-1)?
It's not -1/2
The slope is not -1/2
http://media.education2020.com/evresources/2003-10-02-00-00_files/i0230004.jpg http://media.education2020.com/evresources/2003-10-02-00-00_files/i0230005.jpg http://media.education2020.com/evresources/2003-10-02-00-00_files/i0230006.jpg http://media.education2020.com/evresources/2003-10-02-00-00_files/i0230007.jpg
@superdavesuper
the perpendicular slope is 1/3
m = 1/3 (perpendicular slope) Since we want this perpendicular line to go through (1,-1), we know that x = 1 y = -1
Plug all of this into y = mx+b, then solve for b
Tell me what you get
is it b. y=1/3x-1/3
What happens when you plug in x = 1 into that equation? What do you get for y?
y=1/3x-4/3
Same question: What happens when you plug in x = 1 into the equation y=1/3x-4/3? What do you get for y?
-1
so that verifies you have the right equation
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