Question

What did I do wrong when given the following function x(t) = 2sin(2t)^2 + cos(4t) I found that the period of 2sin(2t)^2 = pi/2 and the period of cos(4t) =pi/2 and therefore the period of the entire function is also pi/2? I know that isn't true but I don't know if I understand why my reasoning was incorrect.

Answer 1

\[x(t) = 2\sin(2t)^2 + \cos(4t)\]