Question

dx/dy for x^5 = -xy^3 at (1,-1)

Answer 1

again?

Answer 2

yeah mate i got a homework load i gotta have some of these to study on. i gotta be ready

Answer 3

isn't this the same one as before?

Answer 4

if my memory serves me it is \(-\frac{4}{3}\)

Answer 5

We used implicit differentiation on that one. For this, we have to find dx/dy

Answer 6

oooh
sorry

Answer 7

Yeah, plus we got (1,-1) the points for this one

Answer 8

flip it

Answer 9

xy^3?

Answer 10

take your answer to the last one'
it was
\[-\frac{5x^4+y^3}{3xy^2}\] and flip it

Answer 11

3xy^2/5x^4+y^3

Answer 12

im a pathetic case i know

Answer 13

yaeh that is right, cept you dropped the minus sign

Answer 14

so, -3xy^2/5x^4+y^3, right mate?

Answer 15

\[\frac{dy}{dx}=-\frac{5x^4+y^3}{3xy^2}\]
\[\frac{dx}{dy}=-\frac{3y^2}{5x^4+y^3}\] almost as if \(\frac{dx}{dy}\) and \(\frac{dy}{dx}\) were actual fractions
hence the notation

Answer 16

oh that's the answer, ya?

Answer 17

yup

Answer 18

you can start from scratch if you like, but that is silly after you did all the work
now at \((1,-1)\) we got \(-\frac{4}{3}\) the first time
this time you will get ... \(-\frac{3}{4}\)

Answer 19

Wait, so is the answer -3/4 or the other one? gahh...

Answer 20

\(\frac{dy}{dx}\) at \((1,-1)\) was \(-\frac{4}{3}\) and so \(\frac{dx}{dy}\) and \((1,-1)\) will be \(-\frac{3}{4}\)

Answer 21

cheers mate love ya always a helpin' hand

Answer 22

cheers to you