Help would really be appreciated! : ) List all of the potential rational zeros of the polynomial function. Do not attempt to find the zeros. f(x)=3x^3+4x^2+x-6. @campbell_st

Question

anonymous · Answer

attachment

anonymous · Answer

@satellite73

campbell_st · Answer

well there is a thing called the rational root theorem 

so look at the factors of the constant, and call end p

look at the factors of the coefficient of the leading term, call the q

then the possible rational roots are

p/q

so in your question the factors of the constant are 

$$p = \pm1, \pm2, \pm3, \pm6$$ 

and the factors of the coefficient of the leading term are 

$$q = \pm 1, \pm 3$$

so look at all the possibilities of p/q

hope it helps

anonymous · Answer

Okay! Thank you so much! : )

anonymous · Answer

That really does help!

campbell_st · Answer

but if you look at what I've written you can eliminate C... no zero listed

and 1st one will be a variation of 

$$\frac{\pm1}{\pm1}$$

which may eliminate a few more choices...

anonymous · Answer

Yep, also I think A can be eliminated.

campbell_st · Answer

lol... well to me... thats the one I'd use... 

I should have said, the 1st possible zero will be 

-1 or 1,

anonymous · Answer

Oh yeah! Sorry about that! I'm really bad at math! :o

anonymous · Answer

Okay, I get how to find the answer now. =)

anonymous · Answer

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