Question

How many atoms are in 2.56 mol of (NH4)3 PO4?

Answer 1

Please quickly answer

Answer 2

calculate the molar mass of the compound .!

Answer 3

Multiply first by the Avogrados number.

Answer 4

yes ,,,15.416 x 10^23 atoms

Answer 5

but that is not the answer on the back. I get 1.54*10powerof24 but answer in the back says 3.08*10powerof25

Answer 6

There are 2.56 x 6 x 10^23 molecules in a mole of the compound,
but each molecule has a lot of atoms that need to be counted.

Answer 7

explain more please

Answer 8

Take the compound description and count how many atoms of each element make up one molecule of the compound. e.g., NH4 has 5 atoms

Answer 9

\[2.56 \text{ mol} (NH_4)_3PO_4\times \frac{6.02 \times 10^{23} \text{ molecules}(NH_4)_3PO_4}{1 \text{ mol}(NH_4)_3PO_4} \times \frac{20 \text{ atoms}}{1 \text{ molecule}(NH_4)_3PO_4}\]

Answer 10

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Answer 11

how many atoms are in \((NH_4)_3 PO_4\)? well, \(3\times(1+4)+1+4=15+5=20\) atoms

Avogadro's constant tells us that \(1\text{ mol}\) contains approximately \(6.022\times10^{23}\) molecules so the total number of atoms is just$$6.022\times10^{23}\cdot20=1.204\times10^{25}$$

Answer 12

But what oldrin said is the number of atoms in one mole. Multiply that by 2.56 to get the answer.