A boat is moving towards east with velocity 4m/s with respect to river water and river is flowing toward north with velocity 2m/s. The wind is blowing towards north with velocity 6m/s. The direction of the flag hoisted on the boat, blown over by the wind is, .--
@eliassaab @ganeshie8 @GirlByte
choices are north-west south-east tan inverse 1/2 with east north
tan inverse 1/2 with east north
the answer is given as north-west direction
u can try vector method to find the resultant...
tried but in vain .!
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Just need to add the two vectors: 4 m/s East and 8 m/s North. arctan(1/2) East of North.
here if i and j are taken as the unit vectors along east and north directions then you have to fined the resultant of the vetors 2i ,2j,4j and then add them up and then simply find the direction cosine of the resultant
boat is moving east with respect to a river flowing north + wind is flowing north, since the flag is hoisted on the boat, it is also moving east, but influenced by the velocity of river + wind
yes @digitalmonk ...but @matricked the answer doesnt say .that ..ur solution doesnt involve 6m/s at all .?
what i came up to is the flag will fly in the direction of velocity of air with respect to boat !
r = river e = earth w = wind b = boat \(Vre = 2j\) \(Vwe = 6j\) \(Vbr = 4i\) \(Vbe = Vbr + Vre = 4i + 2j \)
yes ..!
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