y=−2x^2−24x−64

Question

y=−2x^2−24x−64

anonymous · Answer

Identify the vertex, equation for the axis of symmetry, domain, range and x- and y-intercepts of the parabola.

I don't wan you to do it, I'd just like some help, please :)

anonymous · Answer

@mathmale

mathmale · Answer

Hello, Steve-O,
First of all, what do you alreasdy know about this topic?  I'd prefer to build on that rather than to start from scratch.

anonymous · Answer

Vertex = (h,k)
I know what domain and range are.

Basically, they didn't give us a formula for this, but if I had that I think I could maybe do it.

mathmale · Answer

y=−2x^2−24x−64 has the same form as
y =  ax^2 + bx + c.

Could you please identify a, b and c?

mathmale · Answer

OpenStudy reports that you're "just looking around."

Note:  once you have a, b and c, 

the vertex x-coordinate is x=-b/2a.  That is also the equation for the axis of symmetry.

anonymous · Answer

a=2, b=24, and c=64 I think

anonymous · Answer

I'm not sure why it says I'm just looking around, I never even closed this tab or anything.

mathmale · Answer

a, b and c are all negative.  Please go back and double-check on that.  Comfortable with that?  If so, write out a, b, and c again.

anonymous · Answer

Oh, I wasn't even paying attention

So a=-2, b=-24, and c=-64?