Rewrite this fraction with all the variables in the numerator.

Question

anonymous · Answer

$$\frac{ 4g }{ h ^{3} }$$

anonymous · Answer

@austinL @mathmale @MisLeadSiren

mathmale · Answer

Ellie, use what you learned in our previous discussion.  You have h^3 in the denominator and are to move it to the numerator using the same rule as before.  Please try this.

anonymous · Answer

So would that become 1/h^-3 ?

mathmale · Answer

Yes!  Now try your hand at re-writing the original expression accordingly.  Everything should end up in the numerator.

anonymous · Answer

$$1/h ^{-3}*4g ?$$

mathmale · Answer

Why the "1/"  ?  Think about this for a moment.  Re-read the instructions for this problem.  :)

anonymous · Answer

Oh crud I thought it said denominator. Ugh. I don't see how I can put them all in the numerator though.

mathmale · Answer

Formerly you had h^3 in the den.  You applied that rule of exp. correctly, ending up with h^(-3) in the numerator.  4g is already in the numerator. 

Try again:

anonymous · Answer

Ugh I'm still lost /.\

mathmale · Answer

$$4g \rightarrow4g$$
$$\frac{ 1 }{ h ^{3} }\rightarrow h ^{-3}$$
Just multiply those two results together.