Question

Find the 5th term of the sequence in which t1 = 8 and tn = -3tn-1.

Answer 1

sorry bro :p

Answer 2

\(\large \bf t_{\color{red}{ 1}}=8\qquad t_{\color{red}{ n}}=-3t_{\color{red}{ n}}-1\qquad t_{\color{red}{ 5}}=-3t_{\color{red}{ 5}}-1\)

Answer 3

hmm

Answer 4

can you post a quick screenshot of the material?

Answer 5

what kind of material this is the formula if thats what you are asking

Answer 6

the actual question

Answer 7

just a quick screenshot of it

Answer 8

\(\bf t_1=8\qquad t_n={\color{red}{ -3}}t_{n-1}\qquad\textit{comomon ratio}={\color{red}{ -3}}\\ \quad \\
5^{th}\ term=4^{th}\ term\cdot {\color{red}{ -3}}\\ \quad \\

\begin{array}{llll}
t&\\
1&8\\
2&8{\color{red}{ (-3)}}\\
3&8{\color{red}{ (-3)}}{\color{red}{ (-3)}}\\
4&8{\color{red}{ (-3)}}{\color{red}{ (-3)}}{\color{red}{ (-3)}}\\
5&8{\color{red}{ (-3)}}{\color{red}{ (-3)}}{\color{red}{ (-3)}}{\color{red}{ (-3)}}\implies 8{\color{red}{ (-3)}}^{n-1}
\end{array}\\ \quad \\
t_{\color{red}{ 5}}=t_1(-3)^{{\color{red}{ 5}}-1}\)

Answer 9

t5=t1(−3)5−1
this is the answer?