How do I simplify rational exponents? Such as, \[{a}^{1/2}({a}^{3/2}-{2a}^{1/2})\]
When you distribute things, you get \(\large a^{3/2+ 1/2} - 2a^{1/2+1/2}\). What do you get when you simplify that? :-)
first multiply through and then deal with the exponents. of course in multiplying, you will be dealing with the exponents, too but in a different way.
\(\bf \Large{ a^{\frac{1}{2}}\left(a^{\frac{3}{2}}-2a^{\frac{1}{2}}\right)\implies a^{\frac{1}{2}}\cdot a^{\frac{3}{2}}-a^{\frac{1}{2}}\cdot 2a^{\frac{1}{2}}\\ \quad \\ \implies a^{\frac{1}{2}+\frac{3}{2}}-a^{\frac{1}{2}+\frac{1}{2}}}\)
hmm got a missing 2 =) \(\bf \Large{ a^{\frac{1}{2}}\left(a^{\frac{3}{2}}-2a^{\frac{1}{2}}\right)\implies a^{\frac{1}{2}}\cdot a^{\frac{3}{2}}-a^{\frac{1}{2}}\cdot 2a^{\frac{1}{2}}\\ \quad \\ \implies a^{\frac{1}{2}+\frac{3}{2}}-2a^{\frac{1}{2}+\frac{1}{2}}}\)
hmmm
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