hey can someone help me with this proof? i have a test tomorrow
@jim_thompson5910
Were you able to get anywhere?
And here is the rotated version (just for a better reference)
i just have the given and reflexive property im not sure where to go from there
Ok, ur next step should be trying to prove <AFD=<BFD
is that the complement theorem?
Correct
And now I'm sure u have all the info to prove two congruent triangles and then prove what u need
dont i need to proove af and bd congruent?
Yes, u will prove that using CPCTC after u prove 2 triangles congruent
can you help me with the next step? im just not sure what goes next
So after the compliment theorem, u have 2 pairs of congruent angles and a pair of congruent sides, would u use SSS,SAS,ASA,.... To prove those 2 triangles congruent. AFD=BFD
but not all 3 sides are congruent
dont you have to prove ad congruent to bd so it would be sas?
No, try looking differently. Wait, did u prove FD=FD for reflexive?
yes
Ok, so this is what u should have <AFD=<BFD fD=FD <ADF=<BDF
i dont have the last one
whats the reason for that?
@nikato
Oh it's from ur given
segment DF bisects angle EDC (given) so that means that angle EDC is cut exactly in half. Each smaller angle that makes up angle EDC is congruent to one another.
Definition of angle bisector^
ok thanks
Join our real-time social learning platform and learn together with your friends!