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Mathematics 13 Online
OpenStudy (anonymous):

hey can someone help me with this proof? i have a test tomorrow

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

Were you able to get anywhere?

jimthompson5910 (jim_thompson5910):

And here is the rotated version (just for a better reference)

OpenStudy (anonymous):

i just have the given and reflexive property im not sure where to go from there

OpenStudy (nikato):

Ok, ur next step should be trying to prove <AFD=<BFD

OpenStudy (anonymous):

is that the complement theorem?

OpenStudy (nikato):

Correct

OpenStudy (nikato):

And now I'm sure u have all the info to prove two congruent triangles and then prove what u need

OpenStudy (anonymous):

dont i need to proove af and bd congruent?

OpenStudy (nikato):

Yes, u will prove that using CPCTC after u prove 2 triangles congruent

OpenStudy (anonymous):

can you help me with the next step? im just not sure what goes next

OpenStudy (nikato):

So after the compliment theorem, u have 2 pairs of congruent angles and a pair of congruent sides, would u use SSS,SAS,ASA,.... To prove those 2 triangles congruent. AFD=BFD

OpenStudy (anonymous):

but not all 3 sides are congruent

OpenStudy (anonymous):

dont you have to prove ad congruent to bd so it would be sas?

OpenStudy (nikato):

No, try looking differently. Wait, did u prove FD=FD for reflexive?

OpenStudy (anonymous):

yes

OpenStudy (nikato):

Ok, so this is what u should have <AFD=<BFD fD=FD <ADF=<BDF

OpenStudy (anonymous):

i dont have the last one

OpenStudy (anonymous):

whats the reason for that?

OpenStudy (anonymous):

@nikato

OpenStudy (nikato):

Oh it's from ur given

jimthompson5910 (jim_thompson5910):

segment DF bisects angle EDC (given) so that means that angle EDC is cut exactly in half. Each smaller angle that makes up angle EDC is congruent to one another.

OpenStudy (nikato):

Definition of angle bisector^

OpenStudy (anonymous):

ok thanks

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