Question

Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4x and y = 2x + 2 intersect are the solutions of the equation 4x = 2x + 2.

Part B: Make tables to find the solution to 4x = 2x + 2. Take the integer values of x between -3 and 3.

Part C: How can you solve the equation 4x = 2x + 2 graphically?

Answer 1

@ranga

Answer 2

i already have part a

Answer 3

Well for B then just make a table, plug in -3 for x and go increasing till you get to +3

Answer 4

that doesnt help how am i suppose to do the table like ....

Answer 5

x (4x) (2x+2)
-3 -12 -4
-2 -8 -2
....

Answer 6

oh

Answer 7

x should go: -3, -2, -1, 0, 1, 2, 3

Answer 8

and i keep going from there .. and do the same table but with a positive 3 as well right.. it would justbe the same thing though except without negatives...

Answer 9

4(-3) = 2(-3) + 2

-12 = -6 + 2

-12 = -4
_______________
4(-2) = 2(-2) + 2

-8 = -4 + 2

-8 = -2
_________________
4(-1) = 2(-1) + 2

-4 = -2 + 2
_________________

4(0) = 2(0) + 2

0 = 2
__________________

4(1) = 2(1) + 2

4 = 4
____________________

4(2) = 2(2) + 2

8 = 4 + 2

8 = 6

_____________________

4(3) = 2(3) + 2
12 = 6 + 2
12 = 8
_____________________

Answer 10

At the x value of 1 they would intersect btw

Answer 11

both of you gave me different table eamples

Answer 12

._. Really? lol, no we didn't

Answer 13

I just put " = "

Answer 14

yeah cuz @ranga told me it should go like -3, -2, -1, 0, 1, 2, 3

Answer 15

.____________. Thats what I did, I plugged in those values for x

Answer 16

dont be rude, not eveyone can be the Socrates of algebra

Answer 17

Both are the same. I showed the table entries in compact form and tHe_FiZiCx99 showed you the details of the calculation.

Answer 18

How was a rude?!? ;~;

Answer 19

I*

Answer 20

x (4x) (2x+2)
-3 -12 -4
-2 -8 -2
-1 -4 0
0 0 2
1 4 4
2 8 6
3 12 8

Answer 21

ok this is the table i made
x (4x) (2x+2)
-3 -12 -4
-2 -8 -2
-1 -4 0
0 0 2
1 4 4
2 8 6
3 12 8

Answer 22

when x = 1, both 4x and (2x+2) yield the same value. So x = 1 is the solution.

Answer 23

omg we got the same one, i feel smarter now, u couldve saved me 2 minutes though haha

Answer 24

^^

Answer 25

ok and for part c should i just use desmos ?

Answer 26

brb

Answer 27

ok

Answer 28

@tHe_FiZiCx99 for part c should i just use desmos ??

Answer 29

To graph it you would need to have a " y = "

Answer 30

ughhhhhh and how do i do that -____________________- >.<

Answer 31

I'm kinda eh on that, though it says " y= 4x" but I'm not entirely sure :l hmm

Answer 32

Got it :DD

Answer 33

Use desmos or a graphing calculator if you have one, or just a simple graph paper to graph these two lines.

Graph: y = 4x and y =2x + 2
Both will be straight lines.
The point where they intersect will be the solution.

Answer 34

y = 4x

y = 2x + 2

Plot that into desmos and you'll get (1,4) which is the solution

4 = 4(1)

4 = 2(1) + 2

4 = 4

Answer 35

They intersect at (1,4)

Answer 36

Yes they should intersect at (1,4) as we already determined from the table where when x = 1, both functions gave us 4.

Answer 37

thats it for part C ?

Answer 38

Yes.

Answer 39

thank you guys so much, can u help me on my new question

Answer 40

I have to get off, cya