Question

Eliminate the parameter.

x = t2 + 2, y = t2 - 4

Answer 1

\[\Large x = t^2 + 2\]can you solve this for t?

Answer 2

t^2 = x - 2

y = (x-2) - 4 = x - 6

Answer 3

Actually solve for t^2, not t. Since you need t^2 in y = t^2 - 4 anyway

Answer 4

wait confused

Answer 5

x-2=t^2

Answer 6

Correct. Now replace the t^2 in y = t^2 -2 with that.

Answer 7

y=(x-2)-2

Answer 8

Good, now just simplify it.

Answer 9

poop, help lol

Answer 10

lol you know how to simplify this :P

Answer 11

im so confused because im n ot getting any of the answers

Answer 12

y = x - 6, x ≥ 1

y = x + 6, x ≥ 1

y = x2 - 6, x ≥ 1

y = x2 + 6, x ≥ 1

Answer 13

like does are the answers

Answer 14

x = t2 + 2, y = t2 - 4

you got t^2 = x-2 correct, but used...

y=(x-2)-2

It's not y = t^2 - 2 ;)

Answer 15

so x-2-2

Answer 16

No no, it's not

y = t^2 - 2 (which you used)

it's

y= t^2 - 4

Answer 17

ohhhh

Answer 18

Got it? :D

Answer 19

nope lol
i got -4x+8

Answer 20

lol wait.

y= t^2 - 4

and t^2 = x-2

Answer 21

yeah no not getting this

Answer 22

Okay. You know

y = t^2 - 4

and t^2 = x-2

right? So replace t^2 in y = t^2 - 4, with x-2.

Answer 23

okay so y=(x-2)-4

Answer 24

Yes :) you had it before... you just used the wrong equation :)

Answer 25

okay now from there what?

Answer 26

I know you can simplify this:

y=(x-2)-4

(there's no need for the brackets now)

Answer 27

x-6

Answer 28

Yep

Answer 29

yay!

Answer 30

:D yay!

Answer 31

Eliminate the parameter.

x = 3t, y = t + 7

would this be sorta the same

Answer 32

Yes, solve for t in terms of x first, then plug it into the y equation

Answer 33

y = x /3+ 7?

Answer 34

Yes :D

Answer 35

AHH YOU ARE TO AMAZING HAAH

Answer 36

haha well you learn fast, good job!

Answer 37

Eliminate the parameter.

x = 4 cos t, y = 4 sin t

Answer 38

x^2 = 16 cos^2 t
y^2 = 16 sin^2 t

x^2 + y^2 = 16 cos^2 t + 16 sin^2 t
x^2 + y^2 = 16 (cos^2 t + sin^2 t)
x^2 + y^2 = 16(1)

x^2 + y^2 = 16

Answer 39

^ is that your working?

Answer 40

Someone was explaining it to me

Answer 41

Do you follow?

Answer 42

What do you mean?

Answer 43

Understand it?

Answer 44

no :(
Like honestly you've been the only person that has made me get math

Answer 45

This one is a bit different to before... you can't just solve for one now.

x = 4 cos t, y = 4 sin t

Square both equations (just square everything in both of them) in the first step, since it'll come in handy later

x^2 = 16 cos^2 t
y^2 = 16 sin^2 t

Answer 46

okay got that

Answer 47

Now add them together, so add everything on the left side and the right side

x^2 = 16 cos^2 t
y^2 = 16 sin^2 t
to get
x^2 + y^2 = 16cos^2 t + 16 sin^2 t

Answer 48

factor now?

Answer 49

Yes, factor out the 16 on the right... and remember sin^2 t + cos^2 t = 1

Answer 50

so it would just be 16(1) yay i got it right

Answer 51

then just x^2 + y^2 = 16

Answer 52

yes! :D

Answer 53

♥♥ thanks

Answer 54

♥♥ welcome