Question

Final tomorrowT_T
A 20.0kg cannon ball is fired from a cannon with a muzzle speed of 1000m/s at an agle of 37.0 with the horizontal. A second ball is fired at an angle of 90.0 Use the law of conservation of energy to find the maximum height reached by each ball.

Answer 1

I know the formula is \[k _{i}+u _{i}=k _{f}+u _{f}\]

Answer 2

Heights are issues of the vertical component of the velocity:

v = 1000 sin(@) @ = 17o first case and 90 o second case.

The energy lost to gravity is m g h,

The kinetic energy is (1/2) m v^2.

(1/2)(m v^2 - m g h = 0 at maximum height

h = v^2/2 m g

Answer 3

my error: @=37 o first case.