Ask your own question, for FREE!
Mathematics 22 Online
OpenStudy (anonymous):

someone please help with two questions?

OpenStudy (anonymous):

I saved the wrong one.

OpenStudy (anonymous):

sup

OpenStudy (anonymous):

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

first one, looks like you are adding 5 each time right? keep adding 5

OpenStudy (anonymous):

second one is the "distributive property" \(a(b+c)=ab+ac\)

OpenStudy (anonymous):

OpenStudy (anonymous):

I have another study guide that i'm trying to fill out tonight for a big bonus extra credit

OpenStudy (anonymous):

\[5x+11\geq -9\] we need to solve this right?

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

What grade you in?

OpenStudy (anonymous):

subtract \(11\) from both sides, get \[5x\geq -20\] then divide both sides by \(5\) to get \[x\geq -4\]

OpenStudy (anonymous):

\[10x-3\leq 27\] is done similarly add \(3\) and divide by \(10\)

OpenStudy (anonymous):

you get pretty much in your head \[x\leq 3\]

OpenStudy (anonymous):

put them together and get \[-4\leq x\leq 3\]

OpenStudy (anonymous):

So c?

OpenStudy (anonymous):

c?

OpenStudy (anonymous):

oh no, it is A

OpenStudy (anonymous):

Oh sorry haha, do my mind helping on this study guide?

OpenStudy (anonymous):

go ahead and ask

OpenStudy (anonymous):

OpenStudy (anonymous):

\[-10x+11y=-6\] solve for \(y\) by adding \(10x\) to both sides and get \[11y=10x+6\]

OpenStudy (anonymous):

then divide both sides by \(11\) giving \[y=\frac{10}{11}x-\frac{6}{11}\]

OpenStudy (anonymous):

the slope is \(\frac{10}{11}\) and the \(y\) intercept is \(-\frac{6}{11}\)

OpenStudy (anonymous):

OpenStudy (anonymous):

it is a polynomial the domain of a polynomial is all real numbers

OpenStudy (anonymous):

for the range, you have to find the vertex do you know how to do that?

OpenStudy (anonymous):

no.

OpenStudy (anonymous):

lol ok, we use \(-\frac{b}{2a}\) which in your case is \(-\frac{-2}{2\times 1}=1\)

OpenStudy (anonymous):

then replace \(x\) by \(1\) and get \(y=1^2-2\times 1+3=1-2+3=-1+3=2\) so the vertex is \((1,2)\)and the range is \[\{y|y\geq 2\}\]

OpenStudy (anonymous):

Ok, so now it automatically has to be b?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

OpenStudy (anonymous):

\[y-y_1=m(x-x_1)\] \[y-3=\frac{4}{7}(x-7)\]

OpenStudy (anonymous):

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

hell i don't know but since the original price in 1985 is 1.25 go with b

OpenStudy (anonymous):

OpenStudy (anonymous):

you really only have one choice here the \(-7\) at the end means it goes "Down 7"

OpenStudy (anonymous):

OpenStudy (anonymous):

jesus how many of these you got?

OpenStudy (anonymous):

It's a study guide to my final next week, it's half of the questions on the final, there are like 100 something on the final, but this is like 40

OpenStudy (anonymous):

at least two hours means \(x+y\geq 2\)

OpenStudy (anonymous):

so its either b or c

OpenStudy (anonymous):

he works less on his backhand than his serve \(x<y\)

OpenStudy (anonymous):

and also \(y>0\)

OpenStudy (anonymous):

so b?

OpenStudy (anonymous):

no i think c because you need \(x<y\)

OpenStudy (anonymous):

OpenStudy (anonymous):

mercifully it is the first one

OpenStudy (anonymous):

i gotta run, good luck

OpenStudy (anonymous):

Thanks, i will finish this study guide :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!