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Mathematics 18 Online
OpenStudy (homeworksucks):

A net force of 5.75 x10^3 N [180 degrees] acts on a mass of 23.0 kg. If, while the force acts, the mass travels through a displacement of 360 m[210 degrees]. what work did the net force do on the object.

OpenStudy (loser66):

@douglaswinslowcooper

OpenStudy (anonymous):

Work = force x distance cos (@) work = (5.75 x 10^3 N)( 360 m( (.866) in Joules

OpenStudy (loser66):

can we have a diagram? @douglaswinslowcooper

OpenStudy (anonymous):

I have not mastered drawing here. Imagine a compass and let the force be to the south and the motion to 30o west of south. We do not know what has constrained it to this direction, but we are told this is what happened. Perhaps it was on a rail.

OpenStudy (loser66):

Thank you

OpenStudy (anonymous):

You are welcome, Winner66.

OpenStudy (homeworksucks):

So we would resolve force and not distance?

OpenStudy (loser66):

@Homeworksucks read his comment, he said: Work = Force x Distance x cos (\(\alpha\))

OpenStudy (homeworksucks):

ok, I see. I originally resolved the distance to be in the same direction as the force, which is apparently wrong.

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