Question

Find the zeros of the function, giving the multiplicity *please help*: f(x)=2(x-5)(x+4)^2

Answer 1

set \(x-5=0\) and solve for \(x\) in your head

Answer 2

similarly set \(x+4=0\) and solve for \(x\)
since the factor is \((x+4)^2\) then the zero (which is \(-4\) ) has "multiplicity 2" because the exponent is 2

Answer 3

So, you dont do anything with the 2 in front of the parenthesis?

Answer 4

no
if something is zero, two times that thing is zero also and vice versa
the constant makes no difference