Question

If 12.6 grams of iron (III) oxide reacts with 9.65 grams of carbon monoxide to produce 7.23 g of pure iron, what are the theoretical yield and percent yield of this reaction?

Answer 1

Welcome to openstudy! U actually posted this chemistry question in the math section.
http://openstudy.com/study#/groups/Chemistry

But I will still help u.

1. Did u find the balanced equation yet?

Answer 2

Yes, Fe2O3 + 2CO -->2Fe + CO2

Answer 3

Next u want to find the limiting reagent

Answer 4

If u don't know how, check this out

http://www.chem.tamu.edu/class/majors/tutorialnotefiles/limiting.htm

Answer 5

moles Fe2O3 = 12.6 g /159.694 g/mol=0.0789
the ratio between Fe2O3 and CO is 1 : 3
moles CO required = 0.0789 x 3 =0.237
actual moles CO = 9.65 g / 28.01 g/mol=0.345 so CO is in excess
the ratio between Fe2O3 and Fe is 1 : 2
theoretical moles Fe = 0.0789 x 2 =0.157
theoretical mass Fe = 0.157 mol x 55.847 g/mol=8.81
% yield = 7.23 x 100/ 8.81 =82.0

Answer 6

how do you know to divide 12.6 by the molar mass?

Answer 7

muchas gracias

Answer 8

No.. This is not a practice exam. This is a module quiz from FLVS so using this answer will be an academic integrity violation. Plus it has a obvious mistake in it.

Mr. Carlyle
FLVS Chemistry Instructor

This question is a violation of the OpenStudy Guidelines. The question is from an online school plus a violation by solicitation for members to unknowingly assist them cheating on an exam. 30653065chem30653065