Question

Write an equation of a line parallel to y = 2/3 x -5 in slope-intercept form that passes through the point (-6, -1).

y= -3x - 1
y= 3x + 6
y= 2/3 x - 6
y= 2/3 x + 3

Answer 1

Bacon

Answer 2

Lol. Ok so do you know formula?

Answer 3

I'm serious D:

Answer 4

I know how to do it but im too lazy ._.

Answer 5

*the slope formula

Answer 6

erm....
y2 - y1
__________________
x2 - x1

Answer 7

help me out? ;-;

Answer 8

Yesh. That is all I remember right now because my brain is really tired. I'm sorry.

Answer 9

You should force shadow to help you. *wink wink*

Answer 10

SHADOW o-o

Answer 11

*whispers* Bribe him with bacon, that will have to work.

Answer 12

@Reneestacha
Write an equation of a line parallel to y = 2/3 x -5 in slope-intercept form that passes through the point (-6, -1)

If the line is parallel, then it will have the same gradient (slope) as y = 2/3 x -5
Therefore, the gradient (slope) is 2/3
now what we can do is form the equation of the parallel line using gradient m=2/3 and that it passes through (-6, -1) Using y-y1=m(x-x1)
I will start you off.
y-(-1)=2/3(x-(-6))
would u be able to go on from here?

Answer 13

Nice marigirl ._.