Question

Simplify:
(there's an attachment)

Answer 1

x^6

Answer 2

\[\log _{e} x = \ln x\] right? how about 3ln3? like, what will happen to the '3' infront??

Answer 3

how did you do it? :)

Answer 4

e^ln(x)=x
and
aln(x)=ln(x^a)
Use these properties. it is very difficult for me to do this sum on a keyboard

Answer 5

ohh, i did not know e^ln(x)=x

Answer 6

@MayankD there's an 'equation' button below the text box :) you can input any equations if you'd like :)

Answer 7

I hope you follow. I skipped a few steps. But this is the method.

Answer 8

Oh god wait. i made another error.

Answer 9

okay :) i forgot to mention earlier that there are four choices for the answer...
a) x^2 b) x^6 c) x^5 d) x^3

Answer 10

Haha! okay :) :)

Answer 11

just give me five. I'll do it for you. I am so new to these apps.

Answer 12

=\[e^{3\ln3 ^{\log_{3} x^2}}\]

=\[e^{\ln3 ^{3\log_{3} x^2}}\]
=\[3 ^{3\log_{3} x^2}\]

=\[3 ^{\log_{3} x^6}\]
=\[ x^6\]

Answer 13

Sorry for all the confusion. The first time i did it i did it right and the second time i messed up while doing it on the equation app. :P

Answer 14

it's okay, im reading it...

Answer 15

Also in the property
\[e^{\ln x}\] =x

\[a^{ \log_{a}x }\] =x
a is any real number

Answer 16

Got it!!! Thanks! :)

Answer 17

:)