Question

Here is another attached problem

Answer 1

@eliassaab can you help me please

Answer 2

ill post the questiion

Answer 3

I helped you yesterday and you disappeared on me.

Answer 4

ok i wont this time im serious

Answer 5

please

Answer 6

area of triangle \(R\) = 3* area of triangle \(S\)

that means area in xy is worth 3 times the area in uv
\(\mathbf{dx dy = 3dudv} \)

Answer 7

for working bounds :
inner integral : 0 -> 1-u
outer integral : 0 -> 1

\(\mathbf{\int \limits_0^{1} ~\int \limits_0^{1-u} (2u+v)^2(u+2v)^3(3dudv)}\)

Answer 8

its same as :

\(\mathbf{\int \limits_0^{1} ~\int \limits_0^{u} (2u+v)^2(u+2v)^3(3dvdu)} \)

Answer 9

\[
\int _0^1\int _0^{1-u}3 (2 u+v)^2 (u+2 v)^2dvdu=\frac{47}{20}
\]

\[

\int _0^1\int _0^u3 (2 u+v)^2 (u+2 v)^2dvdu=\frac{77}{5}
\]

Answer 10

oops ! somethign went wrong...

Answer 11

@ganeshie8, you r first integral is the right answer.

Answer 12

ahh i see my mistake, thnks @eliassaab :)

Answer 13

YW