Question

Find the area under curve y= 1 / cos^2 t between t=0 and t=Pi/4

Answer 1

\[\int\limits_{0}^{\pi/4}\frac{ 1 }{ \cos^2t}dt\]

Answer 2

integration of \[\sec^2t\] is tan(t)
then puting the limits u get tanpi/4 - tan0
=1-0=1 sq.unit

Answer 3

Where did sec^2 t come from?

Answer 4

Ok I got it - fundamental identities. Thanks!

Answer 5

anytime .:) ..