Question

critical points of f(x)=x-2sqrt(x)

Answer 1

step1 : find the derivative

Answer 2

its confusing

Answer 3

guide me?

Answer 4

which part ? do it step by step...
sure :)

Answer 5

which part ? do it step by step...
sure :)

Answer 6

which part ? do it step by step...
sure :)

Answer 7

:)

Answer 8

\(\large f(x) = x - 2 \sqrt{x}\)

differentiate both sides, and tell me wat u got

Answer 9

i dont undesrtand differentiations much

Answer 10

its easy, just remember below formula :-

derivative of
\(\large x^n\)

is

\(\large nx^{n-1}\)

Answer 11

oh...
i am just totally lost. I hope you can still help

Answer 12

\(\large f(x) = x - 2 \sqrt{x}\)
is same as
\(\large f(x) = x^1 - 2 x^{\frac{1}{2}}\)

differentiate both sides

\(\large f'(x) = 1x^{1-1} - 2 \frac{1}{2}x^{\frac{1}{2}-1}\)

\(\large f'(x) = 1x^{0} - x^{-\frac{1}{2}}\)

\(\large f'(x) = 1 - \frac{1}{\sqrt{x}}\)

Answer 13

see if you're okay so far
btw this question is from 'calculus' right ?

Answer 14

ya 12th grade

Answer 15

you got the 1st derivative im not sureabout whats next

Answer 16

okay good :)
next set \(f'(x)\) to 0 and solve x.
that gives the cirtical points

Answer 17

Im confused w/ the fractions :'(

Answer 18

\(\large 1 - \frac{1}{\sqrt{x}} = 0\)

solve \(x\)

Answer 19

(-1, 0)?

Answer 20

\(\large 1 - \frac{1}{\sqrt{x}} = 0\)

\(\large 1 = \frac{1}{\sqrt{x}} \)

\(\large 1 = \sqrt{x} \)

\(\large 1 = x \)

Answer 21

pluggin \(x = 1\) in the given equation :-
y = 1 - 2sqrt(1) = 1-2 = -1

thus, the oly critical point for given equation is (1, -1)

Answer 22

Thanks, Rebecca! :)

Answer 23

u wlc (: