Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

Use the Law of Sines to solve for the measure of angle C. A=150, a=6, c=4

OpenStudy (jdoe0001):

|dw:1389819290839:dw|

OpenStudy (anonymous):

would it be 4sin150=6sinC

OpenStudy (jdoe0001):

yeap

OpenStudy (anonymous):

i got 2=6sinC and don't know what to do

OpenStudy (jdoe0001):

\(\bf \cfrac{sin(150^o)}{6}=\cfrac{sin(C)}{4}\implies \cfrac{4sin(150^o)}{6}=sin(C)\)

OpenStudy (anonymous):

1/3?

OpenStudy (jdoe0001):

yes,\(\bf \times sin(150^o)\)

OpenStudy (anonymous):

1/6?

OpenStudy (anonymous):

that makes no sense to me.. the other angles are whole numbers.. how is it possible C is only 1/6?

OpenStudy (anonymous):

You have to take the inverse of sin to get the angle.

OpenStudy (jdoe0001):

sorry the site is getting a bit laggy

OpenStudy (jdoe0001):

as pointed out by coolsday , that's just the SINE function value, not the angle itself

OpenStudy (anonymous):

so what do i do next?

OpenStudy (jdoe0001):

\(\bf \cfrac{sin(150^o)}{6}=\cfrac{sin(C)}{4}\implies \cfrac{4sin(150^o)}{6}=sin(C)\implies \square =sin(C)\\ \quad \\ sin^{-1}(\square )= sin^{-1}[sin(C)]\implies sin^{-1}(\square )= \measuredangle C\)

OpenStudy (anonymous):

i'm sorry... i'm still not understanding

OpenStudy (jdoe0001):

hmmm are you using Internet Explorer by any chance?

OpenStudy (anonymous):

no, google chrome

OpenStudy (jdoe0001):

hmm ... so... .ahemm.... \(\bf \cfrac{sin(150^o)}{6}=\cfrac{sin(C)}{4}\implies \cfrac{4sin(150^o)}{6}=sin(C)\implies \square =sin(C)\\ \quad \\ {\color{red}{ sin^{-1}}}(\square )= {\color{red}{ sin^{-1}}}[sin(C)]\implies {\color{red}{ sin^{-1}}}(\square )= \measuredangle C\)

OpenStudy (anonymous):

so i have to take the inverse of 1/6?

OpenStudy (jdoe0001):

yes, the inverse of whatever the left-side yielded

OpenStudy (anonymous):

well the sin inverse of 1/6

OpenStudy (jdoe0001):

yes

OpenStudy (anonymous):

i forgot my calculator at school and cant find an online calculator with inverse sin

OpenStudy (jdoe0001):

www.desmos.com

OpenStudy (anonymous):

still not seeing inverse sin

OpenStudy (jdoe0001):

click on [Functions ] button

OpenStudy (anonymous):

i did and all i see is sin cos tan csc sec cot.

OpenStudy (anonymous):

so would that be the answer?

OpenStudy (jdoe0001):

www.speedcrunch.org <--- in case you need a calculator

OpenStudy (anonymous):

didnt mean to resend that

OpenStudy (jdoe0001):

\(\bf {\color{red}{ sin^{-1}}}(\square )= \measuredangle C\implies 9.59^o\approx \measuredangle C\)

OpenStudy (anonymous):

9.59 is angle c?

OpenStudy (jdoe0001):

yeap

OpenStudy (anonymous):

thank you so much!!

OpenStudy (jdoe0001):

yw

OpenStudy (anonymous):

I think you should recheck your calculations again. The sine function value is not 1/6.

OpenStudy (anonymous):

i really don't know how do this problem at all

OpenStudy (anonymous):

|dw:1389821643934:dw| cross multiply |dw:1389821680508:dw| The way you are solving for the angle is correct, it is just that you made a mistake in your calculations in step 1

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!