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Mathematics 14 Online
OpenStudy (anonymous):

Can anyone help me with a geometry problem? I will medal and fan.

OpenStudy (anonymous):

i cant access that url... whats the question? btw idk if i can help so i need to see the question to know

OpenStudy (anonymous):

Nick makes the chart shown below to prove that triangle APD is congruent to triangle BPC. —————————————————————————————————— Statements Justifications In triangles APD and BPC; AP = PB P is the vertex of the equilateral triangle In triangles APD and BPC; AD = BC Sides of square ABCD are equal In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° and angle ADP = angle BCP = 90° - 60° = 30° Triangles APD and BPC are congruent SAS postulate —————————————————————————————————— What is the error in Nick's proof? He uses the SAS postulate instead of AAS postulate to prove the triangles congruent. He assumes that AP = PB because P is the vertex of the equilateral triangle. He uses the SAS postulate instead of SSS postulate to prove the triangles congruent. He writes the measure of angles ADP and BCP as 30° instead of 45°.

OpenStudy (anonymous):

|dw:1389820212656:dw| The figure looks like this

OpenStudy (anonymous):

sorry... cant help on this.. :/ i hope someone else can though :(

OpenStudy (anonymous):

I already chose my answer I was just hoping someone could confirm.

OpenStudy (anonymous):

@undeadknight26 can you help me possibly?

OpenStudy (anonymous):

@amoodarya

OpenStudy (anonymous):

@quixoticideals

OpenStudy (amoodarya):

i cant access to pix but what do want to prove ?

OpenStudy (anonymous):

Well, I'm pretty sure that Nick was wrong in assuming that AP = PB just because P is the vertex of the equilateral triangle. I was hoping to get either some back up, or an explanation as to why I'm wrong.

OpenStudy (amoodarya):

|dw:1389820976260:dw|

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