A line passes through the points(-10,-4) and(-1,2) . What is the y-intercept of the line?
Ok, find the slope then put it into point slope form then convert that into slope intercept form, which is y = mx + b where b is the y intercept
To find the slope put your coordinates into M = (Y2-y1)/(X2-x1) M = 2-(-4)/-1-(-10) M = 2 +4/ -1+10 Solve that
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ -10}}\quad ,&{\color{blue}{ -4}})\quad &({\color{red}{ -1}}\quad ,&{\color{blue}{ 2}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green} m}(x-{\color{red}{ x_1}})\qquad \textit{plug in your values and solve for "y"}\)
=.=
you'd end up with something like \(\large \begin{array}{llll} y=\square x&+\square \\ &\ \uparrow \\ &\textit{y-intercept} \end{array}\)
so my y-intercept is -4
Well did you find your slope first?
yes
slope was 2/9
6/9
6/9 was not none of the answers
Simplified is 2/3 So, y-1y=2/3(x-x1) y -(-4)=2/3x + 6.7 y + 4 = 2/3x + 6.7 -4 -4 y = 2/3x + 2.7 What're the options, I'm pretty sure 0.66666666666666666666666666666667 rounded is 6.7
Typo, 6.6666666666666666666666666666667 *
What're the options, I wanna make sure :p
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ -10}}\quad ,&{\color{blue}{ -4}})\quad &({\color{red}{ -1}}\quad ,&{\color{blue}{ 2}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ 2}}-({\color{blue}{ -4}})}{{\color{red}{ -1}}-({\color{red}{ -10}})}\implies \cfrac{6}{9} \\ \quad \\ y-({\color{blue}{ -4}})={\color{green} {\cfrac{6}{9}}}(x-({\color{red}{ -10}}))\implies y+4=\cfrac{6}{9}(x+10)\)
@jdoe0001 6/9 simplfiys to 2/3
yes :)
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