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Mathematics 22 Online
OpenStudy (anonymous):

Write using only positive exponents. 36x^-4y^2z^0/5x^2y^-3z^-2

OpenStudy (anonymous):

OpenStudy (anonymous):

There is the problem and the A B C are the options of answers :)

OpenStudy (jdoe0001):

\(\bf a^{-{\color{red} n}} = \cfrac{1}{a^{\color{red} n}}\qquad a^{{\color{red} n}} = \cfrac{1}{a^{-{\color{red} n}}}\\ \quad \\ \quad \\ \cfrac{36x^{-4}y^2z^0}{5x^2y^{-3}z^{-2}}\implies \cfrac{36}{5x^2}\cdot \cfrac{x^{-4}}{1}\cdot \cfrac{1}{y^{-3}}\cdot \cfrac{1}{z^{-2}}\cdot \cfrac{z^0}{1}\)

OpenStudy (jdoe0001):

keep in mind that anything raised to 0, is 1, except for 0 itself, so \(\bf z^0 = 1\)

OpenStudy (jdoe0001):

\(\bf \cfrac{36x^{-4}y^2z^0}{5x^2y^{-3}z^{-2}}\implies \cfrac{36}{5x^2}\cdot \cfrac{x^{-4}}{1}\cdot \cfrac{1}{y^{-3}}\cdot \cfrac{1}{z^{-2}}\cdot \cfrac{z^0}{1}\\ \quad \\ \cfrac{36}{5x^2}\cdot \cfrac{1}{{\color{red}{ \square ?}}}\cdot {\color{red}{ \square ?}}\cdot {\color{red}{ \square ?}}\cdot \cfrac{z^0}{1}\)

OpenStudy (anonymous):

I got A. thank you so much!

OpenStudy (jdoe0001):

yw

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