Question

I need help writing a sine function

Amp:4 period 3(pi) horizontal shift 1 unit right vertical shift 6units up

Answer 1

The basic sine function form is \(f(x)=a\sin(k(x-b))+c\). Amplitude being 4 implies a = 4. Period being \(3\pi\) implies \[3\pi=\frac{2\pi}{k}\text{ then solve for k.}\] The horizontal shift 1 unit to the right implies b = +1 (positive because to the right.) Vertical shift 6 units up implies c = +6 (positive because upward.)

Answer 2

Ok great thank you

Answer 3

your welcome. :)

Answer 4

Would K be 2/3

Answer 5

yes. :)

Answer 6

Thanks :)

Answer 7

So it would look like f(x) = 4sin (2/3x+1))+6

Answer 8

Nope. It should be \(f(x)=4\sin\left(\frac{2}{3}(x-(+1))\right)+(+6)\)

Answer 9

Ok

Answer 10

:))