Question

Calc 2 - Indefinite Integrals (image)

Answer 1

\[\int\limits_{1}^{5}3t²dt=124 \]

Answer 2

thanks man, howd you get that?

Answer 3

\[F(t)=t³\] and \[f(t)=F'(t)\]
So \[f(t)=d(t³)/dt=3t²\]
All that's left it's to integrate and substitute

Answer 4

Can you show me the last step of integrating and substituting?

Answer 5

\[\int\limits_{a}^{b} ct^{n}dt=[ct^{n+1}/(n+1)]_{a}^{b}\]
In your case\[ a=1,b=5,c=3,n=2\]
So substituting you have
\[=[3*t^{2+1}/(2+1)]_{a}^{b}\]
\[=[t^{2+1}]_{1}^{5}=t^{3}|_{a}^{b}\]
All that's left it's to evaluate, always above limit minus the other
\[=(b^{3}-a^{3})=(5^{3}-1^{3})=124\]

Sorry for taking so long, first time using this lol

Answer 6

no problem, thanks so much!