Question

Find the period of the function.

y = 5 cos one divided by twox

Answer 1

Period (T) is inverse of frequency (f)
Normal form of a sine/cosine is sine(2*pi*f*t), t=x (in your case)
If you have
cos(1/2x)
match the arguments of the functions and solve
2*pi*f*x=1/2x

Answer 2

i dont understand what your saying

Answer 3

Sine and cosine are periodic functions
When you study periodic functions they are always in the form of cos(2*pi*f*x)
The function you gave is also in that form except the terms "2*pi" and "f" are already multiplied so you don't see it that easy
By rule they are implicitly there
So you can use "magic" (not really) of matching both arguments (whatever is inside the trig function) and you can get the frequency

When you get the frequency (letter "f" ) you can get the period (is represented as "T")
T = 1/f

Answer 4

4π

5

pi divided by two

five pi divided by two
these are my answer choices

Answer 5

\[2\pi*fx=(1/2)x\]
\[2\pi*f=(1/2)\]
\[f=1/(4\pi)\]

\[T=1/f=1/(1/4\pi)=4\pi\]