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Mathematics 8 Online
OpenStudy (anonymous):

Put the following linear inequalities into standard form: 2x+y<= 5 5x-(1/3)y <= 6

OpenStudy (mathmale):

It would help me, and perhaps help y ou as well, if you'd look up "standard form" for a linear inequality. Personally, I'd rewrite the first inequality as y<=5-2x.

OpenStudy (anonymous):

can you help me with the second one. y should be isolated

OpenStudy (mathmale):

The second one is a bit harder because of that (1/3). But all'snot lost! We could remove fractions from this problem by multiplying the entire inequality bye 3 (this cancels out the (1/3) ). would you mind doing that now and typing the results here?

OpenStudy (anonymous):

its a -1/3

OpenStudy (anonymous):

negative

OpenStudy (anonymous):

do i multiply by -3

OpenStudy (mathmale):

I'd suggest y ou multiply by +3 now for reasons I'll explain later.

OpenStudy (anonymous):

-1y<=16-15x

OpenStudy (mathmale):

Where you have a 16, I have an 18. Mind checking your work?

OpenStudy (anonymous):

that should be an 18 my mistake

OpenStudy (anonymous):

y<=-18+15x

OpenStudy (mathmale):

A minute or two back you gave me \[-y \le 16-15x \rightarrow -y \le 18-15x.\]

OpenStudy (anonymous):

forget the 16 man

OpenStudy (mathmale):

I see that you then tried changing that -y to +y. This is tricky, however. If you either multiply an inequality by a (-) number, y ou must then reverse the direction of the inequality sign. Does that ring a bell?

OpenStudy (anonymous):

nope cuz my professor stinks

OpenStudy (mathmale):

Start with my very last inequality, above, and multiply everything by -1, and then change the direction of the inequality sign.

OpenStudy (anonymous):

y>=-18+15x

OpenStudy (mathmale):

Beautiful. Perfect. Excellent. Take notes on our conversation, so that you'll have something to review and practice before your next exam.

OpenStudy (anonymous):

ok thanks!

OpenStudy (mathmale):

My great pleasure, Brent! "See" you again soon on OpenStudy.

OpenStudy (anonymous):

why couldnt i have just multiplied by -3

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