Put the following linear inequalities into standard form: 2x+y<= 5 5x-(1/3)y <= 6
It would help me, and perhaps help y ou as well, if you'd look up "standard form" for a linear inequality. Personally, I'd rewrite the first inequality as y<=5-2x.
can you help me with the second one. y should be isolated
The second one is a bit harder because of that (1/3). But all'snot lost! We could remove fractions from this problem by multiplying the entire inequality bye 3 (this cancels out the (1/3) ). would you mind doing that now and typing the results here?
its a -1/3
negative
do i multiply by -3
I'd suggest y ou multiply by +3 now for reasons I'll explain later.
-1y<=16-15x
Where you have a 16, I have an 18. Mind checking your work?
that should be an 18 my mistake
y<=-18+15x
A minute or two back you gave me \[-y \le 16-15x \rightarrow -y \le 18-15x.\]
forget the 16 man
I see that you then tried changing that -y to +y. This is tricky, however. If you either multiply an inequality by a (-) number, y ou must then reverse the direction of the inequality sign. Does that ring a bell?
nope cuz my professor stinks
Start with my very last inequality, above, and multiply everything by -1, and then change the direction of the inequality sign.
y>=-18+15x
Beautiful. Perfect. Excellent. Take notes on our conversation, so that you'll have something to review and practice before your next exam.
ok thanks!
My great pleasure, Brent! "See" you again soon on OpenStudy.
why couldnt i have just multiplied by -3
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