Question

SIMPLIFY :) Photo of problem in comments

Answer 1

Those are the choices underneath for the answers

Answer 2

This requires you to get the lowest common denominator. So, to start lets find the lowest common denominator.

Answer 3

I'm not sure.. a ?

Answer 4

\[\frac{ 1 }{ a-b } + \frac{ 4 }{ b-a }-\frac{ 8 }{ a+b }-\frac{ 11a-5b }{ b^2 -a^2}\]

Answer 5

Do you notice a pattern. can you factor (b^2-a^2) for me?

Answer 6

(b+a)(b-a) ?

Answer 7

Yes! now we can write the equation as \[\frac{ 1 }{ a-b } + \frac{ 4 }{ b-a }-\frac{ 8 }{ a+b }-\frac{ 11a-5b }{ (b+a)(b-a)}\]

Answer 8

now look at all the other denominators. One has a (b-a) another has a (b+a) but one of them neither so we need to incorporate it to the lowest common denominator.

Answer 9

how??

Answer 10

\[\frac{ 1 }{ a-b }\times \frac{ (b-a)(b+a) }{ (b-a)(b+a) } + \frac{ 4 }{ b-a }\times \frac{ (b+a)(a-b) }{ (b+a)(a-b) }-\frac{ 8 }{ a+b }\times \frac{ (b-a)(a-b) }{ (b-a)(a-b) }-\frac{ 11a-5b }{ (b+a)(b-a)}\times \frac{ a-b }{ a-b }\]

Answer 11

leaving that aside we have a denominator

(a-b)(b-a)(a+b)

simplify the numerators.