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OpenStudy (anonymous):
the % H in HCI=? a.2.8 b.3.77 c.5 d.97.2
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OpenStudy (anonymous):
Mass of one hydrogen atom: 1.01 amu Mass of one chlorine atom: 35.45 amu Mass percent Cl in HCl = 35.45 / (1.01 + 35.45) = 35.45 / 36.46 = 97.2%
OpenStudy (anonymous):
So to get %H subtract %CL from 100 so what is 100-97.2ish
OpenStudy (anonymous):
2.8 thanks
OpenStudy (anonymous):
Yep.
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