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Mathematics 9 Online
OpenStudy (anonymous):

Determine whether the sequence,y converges or diverges. If it converges, find the limit. y=square root (n+1)

OpenStudy (loser66):

just give you a trick, replace some values of n to see whether it increases or decreases if it decreases, it tends to converge for example n =0 , --> y =1 n=1 -----> y = sqrt (2) n=3 ---------> y = sqrt(3) n=4 ---------> y = 2 ohohoh,,,,, it's increasing, so it diverges

OpenStudy (loser66):

got me?

OpenStudy (anonymous):

thank you. I am a rookie learning limits. this topic is a bit hard for me compared to hyperbola, parabola and ellipse. Yeah I got your meaning.

OpenStudy (loser66):

and when you "think" it diverges, use diverge test to put it in logic and get credit

OpenStudy (loser66):

for your problem, I "think" it diverges, so I apply divergence test which says If \(lim_{n\rightarrow \infty}a_n\neq0\) then \(\sum a_n\)diverges

OpenStudy (loser66):

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