Question

please help ill give medal
y=x^2-2x+1
A.
1
B.
–1
C.
–2
D.
2

Answer 1

do you wanna x of vertex ( axis of symmetry)?

Answer 2

Use the zeros of the following quadratic to find the x-value of the vertex.

Answer 3

thats simple put all the stuff in quadratic formula i.e
a= 1 , b= -2, c=1
in
(-b +- underroot (b^2 - 4 ac )) / 2a
root will be 1

Answer 4

you lost me at this part (-b +- underroot (b^2 - 4 ac )) / 2a

Answer 5

I forgot latex
just hold on try to show you equation

Answer 6

try to turn it in standard form
y=a(x-b)^2+b

Answer 7

y=x^2-2x+1=(x-)^2
so
x of vertex is x=1

Answer 8

put x=1 in it to find y of vertex

Answer 9

\[\frac{ -b \pm \sqrt{b^{2}- 4ac} }{ 2a }\]

Answer 10

thats quadratic formula :)

Answer 11

annas
you say these are the roots of quadratic

Answer 12

lol smart guy y= (1)^2 -2 (1) + 1 = 1 - 2 +1= 2 - 2 = 0
xD not an option