y - 5x = -6 and 3y - 15x = -12
a. one b. two c. infinitely many d. none
@courter98
How do you think you start?
-6 + 5x = y
wait I think I might have it, hold on
You have to get the two equations to be divisible by the same number. Since in the second equation, they are all divisible by 3. You would multiply the first equation by 3
y - 15
How did you get that?
6 + 5 x 3 = 15 I honestly don't know how to do this, im trying to study for semester and unit exams. can you show step by step on how to do it
Sure. Give me one sec
y - 5x = -6 and 3y - 15x = -12 have to both be divisible by the same number. 3y - 15x = -12 are all divisible by 3.
So to get y - 5x = -6 divisible by 3 you have to multiply all of them by 3. y(3) -5x(3) = -6(3)
Do you understand so far?
yes, i'm writing this down
Sorry my internet cut out
You should have gotten 3y - 15x = -18
my computer is acting weird, you can continue
3y - 15x = -18 3y - 15x = -12 Now all you do is subtract
ok
The y's and the x's cancel out. so you are left with 0 = -6. 0 = -6 is never true. Therefore, the answer is no solutions
thanks so much, I hope I do well with these type of questions on the exams
I wish you the best of luck! Is this algebra 1?
yes
Ok. If you need any more help, just let me know. I did really good in algebra 1
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