Question

.2. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation:
CH4 + NH3 + O2 HCN + H2O
You have 8 g of methane and 10 g of ammonia in excess oxygen.

• Which reagent is limiting?

Answer 1

work out the molecular mass of ammonia and methane to see how the relative masses react

Answer 2

can you do that?

Answer 3

if you check the periodic table you'll see that atomic mass of H is 1, C is 12 and N is 14
(very close to these figures)

so from the equation 12+4 grams of methane reacts with 14 + 3 Grams of ammonia

that is 16 g CH4 reacts with 17 g NH3

so by proportion 8 grams of CH4 reacts with 8.5 grams of NH3

Answer 4

so which reagent is limiting?

Answer 5

Thank you @Nuge