Question

Find the equation of a line given the point and slope below. Arrange your answer in the form y = mx + b, where b is the constant.

(-6, 1)
m = 6

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&({\color{red}{ -6}}\quad ,&{\color{blue}{ 1}})\quad
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= 6
\\ \quad \\

y-y_1={\color{green} m}(x-x_1)\qquad \textit{plug in your values and solve for "y"}\)

Answer 2

my answer is y=6x-37. Is my answer correct

Answer 3

\(\bf y-(1)={\color{green} 6}(x-(-6))\implies y-1=6(x+6)\implies y=6x+37\)

Answer 4

Thanks. Can you help me with one more?

Answer 5

ok

Answer 6

(10, 11)
m = -9

Answer 7

\(\bf \begin{array}{lllll}
&x_1&y_1\\
&({\color{red}{ 10}}\quad ,&{\color{blue}{ 11}})\quad
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= -9
\\ \quad \\

y-(11)={\color{green} {-9}}(x-(10))\implies y=-9(x-10)+11\)