I Need Help With A Few Questions. Can Someone Help Me!
post one
What are the questions, ill try to help
Umm.. Show Work… Please.. & Find An Equation Of The Line Containing The Points. (-1,4) And (3,12)
you need the slope first do you know how to find it?
Uh I Thinkk Soo.
\[\frac{\color{red}{y_2}-\color{green}{y_1}}{\color{blue}{x_2}-\color{pink}{x_1}}\] \[\color{red}{y_2}=\color{red}{12},\color{green}{y_1}=\color{green}4\] \[\color{blue}{x_2}=\color{blue}3,\color{pink}{x_1}=\color{pink}{-1}\]
let me know what you get
Yeah i know that part. How Do I Solve Again?
plug them in, you get \[\frac{12-4}{3-(-1)}=\frac{8}{4}=2\] and that is your slope
Thank You. I Have Another Problem. Help?
Is That All For This Problem?
then to find the equation of the line, use the "point slope" formula \[y-y_1=m(x-x_1)\] with \[m=2,y_1=12,x_1=3\] you are not done once you find the slope, you have to do that as well
\[y-y_1=m(x-x_1)\\ y-12=2(x-3)\]and you are probably still not done, you may have to solve for \(y\) to write it in the form \(y=mx+b\)
Thanks.
yw
Another Problem..
Write An Equation Of The Line That Passes Through The pint (5,6) With Slope 2
Point*
that is even easier, because you don't have to find the slope first, you already know it
Slope =2
\[y-y_1=m(x-x_1)\] put \(m=2,x_1=5,y_1=6\) plug them in directly in to the point slope formula
Okay. Let Me Do That Real Fast.
So Far It's…. y-6=(x-5) ??
you missed the 2
y-6=2(x-5) **
better then multiply out on the right using the distributive property
Multiply By 2?
yes, distribute the 2 to remove the parentheses
y-6=2x-5 ??
y-6=2x-15 ?
no
don't forget the distributive law you have to multiply both terms by 2
Ugh! Sorry.
i forgot.
\(y-6=2x-10\) is what you are looking for
UGH!
\[y-6=2(x-5)\\ y-6=2\times x+2\times (-5)\\ y-6=2x-10\] then add \(6\) to both sides and get \[y=2x-4\]
Thats All????
lol yeah, all
Thanks Lol. Hmmm Write The Slope- Intercept Form Of The Equation Of The Line Passing Through The Point (2,6) And Parallel To The Line y=-5x+4…..
the line \(y=-2x+4\) has slope \(-5\) repeat the process above with \(m=-5,x_1=2,y_1=6\)
oops i meant the line \(\large y=-5x+4\) has slope \(-5\)
Do I Write That Down?
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