calculate the Gibbs free energy change for the following reaction
\[ATP \rightarrow ADP+ P_{i}\] if the reaction occurs at 68 degrees F and the change in heat \[\Delta H\] = 19,070 cal and the change in entropy = 90 cal/ degree K
Would this help? http://www.chem.tamu.edu/class/majors/tutorialnotefiles/gibbs.htm
no not really
Gibbs Free Energy (G) - The energy associated with a chemical reaction that can be used to do work. The free energy of a system is the sum of its enthalpy (H) plus the product of the temperature (Kelvin) and the entropy (S) of the system: G=H-TS That basically says it. You have H, T, and S.
what does this cal mean?
cal is the unit for energy or heat change.
so the cal part doesn't really matter I still plug it in the same
Well since both H and S use cal, yes, you just plug in.
I can't translate the temperature. my calculator is being stupid
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